25=25(0)-16t^2

Solution for 25=25(0)-16t^2 equation:

25=25(0)-16t^2

We move all terms to the left:

25-(25(0)-16t^2)=0

We get rid of parentheses

16t^2-250+25=0

We add all the numbers together, and all the variables

16t^2-225=0

a = 16; b = 0; c = -225;
Δ = b2-4ac
Δ = 02-4·16·(-225)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120}{2*16}=\frac{-120}{32}
=-3+3/4
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120}{2*16}=\frac{120}{32}
=3+3/4
$